The General's Horse Drinking Problem in Quadratic Functions (Part 2)
2019-09-06 06:36
This GeoGebra applet demonstrates the classic geometric optimization problem known as the General's Horse Drinking within the context of quadratic functions. By constructing quadratic function graphs, symmetric points, and line segments, it dynamically illustrates how to use axial symmetry transformations to convert the sum of broken line segments into a straight line segment, thereby finding the
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<condition showObject="hint ≥ 1 ∧ hint ≤ 3"/>
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<lineStyle thickness="5" type="20" typeHidden="1" opacity="178"/>
<eqnStyle style="explicit"/>
<outlyingIntersections val="false"/>
<keepTypeOnTransform val="true"/>
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<expression label="text2" exp=""因 $M$ 在对称轴,$\textcolor{#00F}{MO}=\textcolor{#08F}{MC}$。""/>
<element type="text" label="text2">
<show object="true" label="false" ev="40"/>
<condition showObject="hint ≥ 1"/>
<objColor r="0" g="0" b="0" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<isLaTeX val="true"/>
<font serif="true" sizeM="1" size="0" style="0"/>
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<expression label="text3" exp=""根据三角不等式,$\textcolor{#08F}{MC}-\textcolor{#090}{MB} \leq \textcolor{#80F}{BC}$""/>
<element type="text" label="text3">
<show object="true" label="false" ev="40"/>
<condition showObject="hint ≥ 2"/>
<objColor r="0" g="0" b="0" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<isLaTeX val="true"/>
<font serif="true" sizeM="1" size="0" style="0"/>
<absoluteScreenLocation x="14" y="198"/>
</element>
<expression label="text4" exp=""最小值发生在 $M,B,C$ 共线时""/>
<element type="text" label="text4">
<show object="true" label="false" ev="40"/>
<condition showObject="hint ≥ 3"/>
<objColor r="0" g="0" b="0" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<isLaTeX val="true"/>
<font serif="true" sizeM="1" size="0" style="0"/>
<absoluteScreenLocation x="14" y="232"/>
</element>
<command name="Segment">
<input a0="M'" a1="B"/>
<output a0="sM'B"/>
</command>
<element type="segment" label="sM'B">
<show object="true" label="false" ev="4"/>
<condition showObject="hint ≥ 4"/>
<objColor r="0" g="255" b="0" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<coords x="10" y="4" z="-120"/>
<lineStyle thickness="5" type="20" typeHidden="1" opacity="178"/>
<eqnStyle style="explicit"/>
<outlyingIntersections val="false"/>
<keepTypeOnTransform val="true"/>
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<expression label="text1" exp=""$\textcolor{#00F}{MO} - \textcolor{#0A0}{MB} = " + (LaTeX[sMO - sMB]) + "$"" />
<element type="text" label="text1">
<show object="true" label="false" ev="8"/>
<objColor r="0" g="0" b="255" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<isLaTeX val="true"/>
<font serif="true" sizeM="1" size="0" style="0"/>
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</element>
<command name="Segment">
<input a0="B" a1="C"/>
<output a0="sBC"/>
</command>
<element type="segment" label="sBC">
<show object="true" label="false" ev="4"/>
<condition showObject="hint ≥ 3"/>
<objColor r="127" g="0" b="255" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<coords x="5" y="2" z="-60"/>
<lineStyle thickness="5" type="0" typeHidden="1" opacity="178"/>
<eqnStyle style="explicit"/>
<outlyingIntersections val="false"/>
<keepTypeOnTransform val="true"/>
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<expression label="text7" exp=""此时 $\textcolor{#00F}{MO}-\textcolor{#090}{MB} =\textcolor{#80F}{BC}=\textcolor{#80F}{" + (LaTeX[SurdText[Distance[B, C]]]) + " }$"" />
<element type="text" label="text7">
<show object="true" label="false" ev="8"/>
<condition showObject="hint ≥ 5"/>
<objColor r="0" g="0" b="0" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<isLaTeX val="true"/>
<font serif="true" sizeM="1" size="0" style="0"/>
<absoluteScreenLocation x="15" y="306"/>
</element>
<command name="Segment">
<input a0="M'" a1="O"/>
<output a0="sM'O"/>
</command>
<element type="segment" label="sM'O">
<show object="true" label="false" ev="4"/>
<condition showObject="hint ≥ 4"/>
<objColor r="0" g="0" b="255" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<coords x="15" y="-6" z="0"/>
<lineStyle thickness="5" type="15" typeHidden="1" opacity="178"/>
<eqnStyle style="explicit"/>
<outlyingIntersections val="false"/>
<keepTypeOnTransform val="true"/>
</element>
<expression label="text5" exp=""可解得对称轴与直线$\textcolor{red}{BC}$ 的交点 $
\textcolor{red}{M=" + (LaTeX[M']) + "}$。"" />
<element type="text" label="text5">
<show object="true" label="false" ev="8"/>
<condition showObject="hint ≥ 4"/>
<objColor r="0" g="0" b="0" alpha="0"/>
<layer val="8"/>
<labelMode val="0"/>
<isLaTeX val="true"/>
<font serif="true" sizeM="1" size="0" style="0"/>
<absoluteScreenLocation x="13" y="266"/>
</element>
<element type="image" label="pic1">
<file name="6806537567ccdaff98c3525a64dca820/[洋葱] 二次函数中的将军饮马-下(0723).jpg"/>
<inBackground val="false"/>
<absoluteScreenLocation x="3" y="493"/> <show object="true" label="false"/>
<condition showObject="blFig ≠ 0"/>
<objColor r="0" g="0" b="0" alpha="1"/>
<layer val="9"/>
<labelMode val="0"/>
<animation step="1" speed="1" type="0" playing="false"/>
</element>
</construction>
</geogebra>